In a pseudo first order hydrolysis of ester i | vedclass

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(B) The average rate of reaction is calculated using the formula:Average rate $= -\frac{\Delta[Ester]}{\Delta t}$Given the concentration of ester at $

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$4.67 	imes 10^{-3} \, mol \, L^{-1} \, s^{-1}$

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(B) The average rate of reaction is calculated using the formula:Average rate $= -\frac{\Delta[Ester]}{\Delta t}$Given the concentration of ester at $t = 30 \, s$ is $0.31 \, mol \, L^{-1}$ and at $t = 60 \, s$ is $0.17 \, mol \, L^{-1}$.Average rate $= -\frac{0.17 - 0.31}{60 - 30} \, mol \, L^{-1} \, s^{-1}$Average rate $= \frac{0.14}{30} \, mol \, L^{-1} \, s^{-1} = 4.67 	imes 10^{-3} \, mol \, L^{-1} \, s^{-1}$.

In a pseudo first order hydrolysis of ester in water,the following results were obtained.
$t/s$ $0$ $30$ $60$ $90$
$Ester/mol\, L^{-1}$ $0.55$ $0.31$ $0.17$ $0.085$

What will be the average rate of reaction between the time interval $30$ to $60$ seconds?

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In a pseudo first order hydrolysis of ester in water,the following results were obtained.$t/s$$0$$30$$60$$90$$Ester/mol\, L^{-1}$$0.55$$0.31$$0.17$$0.085$What will be the average rate of reaction between the time interval $30$ to $60$ seconds?